纳金网

标题: 如何判断全角半角？ [打印本页]

---

作者: 她。    时间: 2013-6-13 09:25
标题: 如何判断全角半角？

int IsChineseOrEnglish(LPCSTR pText)
{
unsigned char sqChar[10];
sqChar[0]=*pText;
sqChar[1]='/0';
if (sqChar[0]>=0xa1)
{
  if (sqChar[0]==0xa3)
  {
   return 1;//全角字符  }
  else
  {
   return 2;//汉字  }
}
else
{
  return 0;//英文,英文标点，数字
}
}
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet)//获得汉字与英文的个数
{
if (pSrc == NULL)
{
  return false;
}
else
{
  int nLen = strlen(pSrc);
  char *pTxt = new char[nLen +1];
  char *pHeader = pTxt;
  //LPCSTR pTxt = pSrc;
  strcpy(pTxt, pSrc);
  pTxt[nLen] = '/0';
  while (*pTxt != '/0')
  {
   int nRet = IsChineseOrEnglish(pTxt);
   switch (nRet)
   {
   case 0:
    ++ nNumEngRet;
    pTxt++;
    break;
   case 1:
   case 2:
    ++ nNumChiRet;
    pTxt++;
    pTxt++;
    break;
   default:
    break;
   }
   
  }
  if (pHeader != NULL)
  {
   delete [] pHeader;
   pHeader = NULL;
  }
  return true;
}
}
下面是完整的测试程序：
#include <windows.h>   
#include <iostream>
using namespace std;
int IsChineseOrEnglish(LPCSTR pText);
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet);ÎĵÄ×Ö·û¸öÊý
int main(int argc,char**argv)   
{  
int nNumChin = 0;
int nNumEng = 0;
GetNumChineseAndNumEnglish("£áÑîСӱYanger7", nNumChin, nNumEng);
cout << "Number of Chinese:" << nNumChin << endl;
cout << "Number of English:" << nNumEng << endl;
return 0;   
}  
int IsChineseOrEnglish(LPCSTR pText)
{
unsigned char sqChar[10];
sqChar[0]=*pText;
sqChar[1]='/0';
if (sqChar[0]>=0xa1)
{
  if (sqChar[0]==0xa3)
  {
   return 1;  }
  else
  {
   return 2;//ºº×Ö
  }
}
else
{
  return 0; }
}
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet){
if (pSrc == NULL)
{
  return false;
}
else
{
  int nLen = strlen(pSrc);
  char *pTxt = new char[nLen +1];
  char *pHeader = pTxt;
  //LPCSTR pTxt = pSrc;
  strcpy(pTxt, pSrc);
  pTxt[nLen] = '/0';
  while (*pTxt != '/0')
  {
   int nRet = IsChineseOrEnglish(pTxt);
   switch (nRet)
   {
   case 0:
    ++ nNumEngRet;
    pTxt++;
    break;
   case 1:
   case 2:
    ++ nNumChiRet;
    pTxt++;
    pTxt++;
    break;
   default:
    break;
   }
   
  }
  if (pHeader != NULL)
  {
   delete [] pHeader;
   pHeader = NULL;
  }
  return true;
}
}

---

欢迎光临 纳金网 (http://c-www.narkii.com/club/)

Powered by Discuz! X2.5